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n in (-oo:+oo)
n^2+8/3 = (10/3)*n // - (10/3)*n
n^2-((10/3)*n)+8/3 = 0
n^2+(-10/3)*n+8/3 = 0
n^2-10/3*n+8/3 = 0
DELTA = (-10/3)^2-(1*8/3*4)
DELTA = 4/9
DELTA > 0
n = ((4/9)^(1/2)+10/3)/(1*2) or n = (10/3-(4/9)^(1/2))/(1*2)
n = 2 or n = 4/3
n in { 4/3, 2 }
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